Skip to main content

Capgemini Coding Q1

 Q).


=> Solution :


#include<iostream>

#include<vector>

#include<algorithm>

using namespace std;


vector<int> removeDupMerge(int a1[],int a2[],int m,int n){

vector<int> mVec;

for(int i=0;i<m-1;i++){

     if(a1[i]!=a1[i+1])

        mVec.push_back(a1[i]);

}

mVec.push_back(a1[m-1]);


for(int i=0;i<n-1;i++){

     if(a2[i]!=a2[i+1])

        mVec.push_back(a2[i]);

}

mVec.push_back(a2[n-1]);


sort(mVec.begin(),mVec.end());

return mVec;

}


int main(){

int m,n;

vector<int> myVec;


cin>>m;

int a1[m];

for(int i=0;i<m;i++)

    cin>>a1[i];


cin>>n;

int a2[n];

for(int i=0;i<n;i++)

    cin>>a2[i];


sort(a1,a1+m);

sort(a2,a2+n);


cout<<"\n\n*******| OUTPUT |*******\n\n";

myVec=removeDupMerge(a1,a2,m,n);


//find median

int median,sVec=myVec.size();


if(sVec%2==0){

    median=(sVec-1)/2 + sVec/2;

}else{

    median=(sVec-1)/2;

}


cout<<myVec[median]<<endl;

}


=>Output :




Comments

Popular posts from this blog

Sum of Digit is Pallindrome or not

  Sum of Digit is Pallindrome or not Given a number N.Find if the digit sum(or sum of digits) of N is a Palindrome number or not. Note:A Palindrome number is a number which stays the same when reversed.Example- 121,131,7 etc. Example 1: Input: N=56 Output: 1 Explanation: The digit sum of 56 is 5+6=11. Since, 11 is a palindrome number.Thus, answer is 1. Example 2: Input: N=98 Output: 0 Explanation: The digit sum of 98 is 9+8=17. Since 17 is not a palindrome,thus, answer is 0. Your Task: You don't need to read input or print aything.Your Task is to complete the function isDigitSumPalindrome() which takes a number N as input parameter and returns 1 if the Digit sum of N is a palindrome.Otherwise it returns 0. Expected Time Complexi...

Menu with 5 option & selected option should appear in text box

Q6. Create a menu with 5 options and selected option should appear in text box. Android Program : Activity_main.xml <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"     xmlns:tools="http://schemas.android.com/tools"     android:id="@+id/activity_main"     android:layout_width="match_parent"     android:layout_height="match_parent"     android:paddingBottom="@dimen/activity_vertical_margin"     android:paddingLeft="@dimen/activity_horizontal_margin"     android:paddingRight="@dimen/activity_horizontal_margin"     android:paddingTop="@dimen/activity_vertical_margin"     tools:context="com.kishanhaldar.program6.MainActivity">                 ...

Closest Number

Closest Number Basic Accuracy: 11.21% Submissions: 1615 Points: 1 Given non-zero two integers N and M . The problem is to find the number closest to N and divisible by M . If there are more than one such number, then output the one having maximum absolute value .   Example 1: Input: N = 13 , M = 4 Output: 12 Explanation: 12 is the Closest Number to 13 which is divisible by 4. Example 2: Input: N = -15 , M = 6 Output: -18 Explanation: -12 and -18 are both similarly close to -15 and divisible by 6. but -18 has the maximum absolute value. So, Output is -18   Your Task: You don't need to read input or print anyth...